The angle of refraction is 15.6 deg. When a ray of light passes from medium 1 to medium 2, the refractive index of medium 2 with respect to 1 is the ratio of the absolute refractive index of medium 2 and medium 1. When light passes from air into diamond, with the given values of refractive indices, According to Snell's law, 1. (A) State Snell’s law of refraction. (b) (I) what is critical angle. Calculate the critical of a medium with refractive index of 1.63. (c) A 600 – glass prism has a refractive index of 1.63. Calculate the angle of: (i) Minimum deviation, (ii) Incidence at minimum deviation, and (iii) Refraction of light passing through the prism at minimum deviation?

A narrow beam of light is incident from air onto a glass surface with index of refraction 1.56. Find the angle of incidence for which the corresponding angle of refraction is one-half the angle of incidence. Hint: You might want to use the trigonometric identity $\sin 2 \theta=2 \sin \theta \cos \theta$. The symbols 1 and 2 stand for the angle of incidence and the angle of refraction, respectively. A special case of this equation is used when light travels from a more-dense medium to a less-dense medium and the refracted ray makes an angle of 90.0° with the normal as it skims along the boundary of the two media. When this

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